5x^2-140x-300=0

Solution for 5x^2-140x-300=0 equation:

5x^2-140x-300=0

a = 5; b = -140; c = -300;
Δ = b2-4ac
Δ = -1402-4·5·(-300)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-140)-160}{2*5}=\frac{-20}{10}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-140)+160}{2*5}=\frac{300}{10}
=30
$